Compute the following sums and give your answers in terms of n.(adsbygoogle = window.adsbygoogle || []).push({});

(a) 1 + 2 + 3 + ... + n

(b) 2 + 4 + 6 + ... + 2n

(c) 1 + 3 + 5 + ... + (2n + 1)

I actually have the answers but there seem to be an error...

For (a) 1 + 2 + 3 + ... + n,

My answer given is n(n+1)/2

For(b) 2 + 4 + 6 + ... + 2n

My answer given is n(n+1)

However, for (c)

My answer given is (2n + 2)(n + 1)/2

If we play with the answer for (a) and (b) for example :

(a) : We take the nth term as 3 and sub it in n(n+1)/2 = 3(3+1)/2 = 6(Which is the correct sum up to the nth term)

But for (c) :

We take the nth term as 3 and sub it in (2n + 2)(n + 1)/2 = (2(3) + 2)(3 + 1)/2 = 16(Which is the sum of the number AFTER the nth term.)

The answer for (c) is incorrect, am I right? Because its the answer give by my tutor.

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# Homework Help: Sum of Arithmetic Series help

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