Sum of the fourth powers of the first n positive integers

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Homework Statement



Find a formula fo the sum of the fourth powers of the first n positive integers

n
∑ i^4
(i=1)


Justify your work using mathematical induction

Homework Equations



so i know the formula for the sum of the cubes of the first n positive integers

k=n+1
∑ = (1^3)+(2^3)+(3^3)+...+(n^3)+((n+1)^3)= {((n+1)^2)((n+2)^2)} / (4)
k=1

I was wondering what was the proof for the sum of the quartic of the first n positive integers

The Attempt at a Solution



This is actually what I started working out and I don't know whether it is right

N
∑ i^4 = (1/30)(N+1)(N)(2N+1)((3N^2)+3N-1)
i=1
 
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Sure, that's right. I know it's right because I looked it up. Just like you, probably. The problem is that you have to prove it's right. Call your sum S(N). Then the inductive step (after you shown it's true for N=1) is to show S(N+1)-S(N)=(N+1)^4. Do you see why? If you see why, that's the important part.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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