Sum of the sum of harmonic series?

Nikitin
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Homework Statement


Does this converge or diverge?

Ʃ1/(1+2+3+4+5...+n), as n---> infinity?

The Attempt at a Solution



I rewrote this into Ʃ(Ʃ1/n) (is it correct?).

I figured that since Ʃ(1/n) diverges, then the sum of each partial sum most (obviously) also diverge.

However, it appears I'm mistaken. Can somebody help?
 
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Nikitin said:

Homework Statement


Does this converge or diverge?

Ʃ1/(1+2+3+4+5...+n), as n---> infinity?


The Attempt at a Solution



I rewrote this into Ʃ(Ʃ1/n) (is it correct?).

I figured that since Ʃ(1/n) diverges, then the sum of each partial sum most (obviously) also diverge.

However, it appears I'm mistaken. Can somebody help?

Is 1/(1+2) equal to (1/1) + (1/2)? Basically, you are claiming that the answer is yes.

RGV
 
oh crap. yeh you're right.
 
1+2+...+n=n(n+1)/2,so compare with the convergent series 2/n(n+1)
 
ahh thanks. i completely forgot that you could rewrite 1+2+3..+n into n(n+1)/2.. thx!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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