Summation by Steps: Calculus Self-Teaching Homework Help

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Homework Help Overview

The discussion revolves around the concepts of summation and integration in calculus, specifically focusing on the operation of summing discrete values derived from a function, 5/sqrt(x). The original poster seeks clarification on how to express this operation and its relationship to integration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the nature of the operation the original poster is attempting, identifying it as discrete summation rather than integration. There are questions about the appropriate formulation for this summation and how to implement it in Wolfram Alpha.

Discussion Status

Some participants have provided guidance on how to express the summation mathematically and how to use Wolfram Alpha for this purpose. There is ongoing exploration of the syntax and potential issues with variable definitions. The original poster has expressed gratitude for the assistance received.

Contextual Notes

There are questions regarding the use of decimal figures in the summation process and whether non-integer steps are permissible, indicating a need for further clarification on the rules governing the operation.

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Homework Statement


I hope this is the right forum for this question.
I am starting to self-teach calculus, could you help me shape my problem?
I am trying to use wolfram:
I know that if I integrate an equation say: 5/\sqrt x, I will get the area underneath that curve
http://www.wolframalpha.com/input/?i=+integrate+y=+5/sqrt(x)+++from+20+to+10^4

Now, I want to summate all the values we get increasing x by x or another value:
5/sqrt20 +5/sqrt40...+5/sqrt 10^4

What do you call this operation? is it still integration, by steps or what?
is it necessary to regulate dx to 20, or what
Can you help me formulate this operation :
integrate y = 5/sqrt x from 20 to 10^4 , step 20 or x or...

THanks for your help

Homework Equations


The Attempt at a Solution

 
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What you are trying to do is just discrete summation. In integration (as interpreted in the Riemann summation sense), the width of the "boxes" that you have divided the area under the curve into approaches infinitely small.

The best way to write your desired operation is simply
\sum_{i = 1}^{500}\frac{5}{\sqrt{20i}}

You could of course, multiply this by another factor of 20 if you want to obtain some sort of "area estimate" through finite-sized boxes.
 
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Fightfish said:
The best way to write your desired operation is simply
\sum_{i = 1}^{500}\frac{5}{\sqrt{20i}}

You could of course, multiply this by another factor of 20 if you want to obtain some sort of "area estimate" through finite-sized boxes.
Thanks, can you tell me how to tell that to wolfram?
 
Wolfram is highly versatile, and there are plenty of help options. But just to give you a quick overview of the syntax, it goes like:

Sum [ func, {counter variable, start value, end value}]
 
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Fightfish said:
Wolfram is highly versatile, and there are plenty of help options. But just to give you a quick overview of the syntax, it goes like:

Sum [ func, {counter variable, start value, end value}]

Probably I messed it up, but there is a variable in the result and I didn't get a single value, can you fix it?
http://www.wolframalpha.com/input/?i=sum+[+5/sqrt(k+x),{k++,+1,+10}]
 
Thanks, that's it.
 
Hi,
it seems impossible to use decimal figures, or is there a particular grammar?
Must the step be an integer , or is it possible to increase the value by a decimal , say by 1/10?
Thanks
 

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