- #1
Engineering Calculating Vx in a Circuit with Superposition and Kirchoff's Laws
- Thread starter Mark Nussbaum
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- Circuits Superposition
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The discussion focuses on calculating Vx in a circuit using superposition and Kirchhoff's Laws. The initial calculation yielded a result of 9.818181V. However, a participant pointed out a sign error in the voltage contribution from the 40-volt source, correcting it to -80/11 instead of +80/11. This highlights the importance of careful sign consideration in circuit analysis. Accurate calculations are crucial for determining the correct voltage in electrical circuits.
- #2
Mark Nussbaum
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- #3
The Electrician
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Mark Nussbaum said:Homework Statement
View attachment 211347
Homework Equations
current/voltage division
V=IR
Kirchoffs Laws
The Attempt at a Solution
and adding all Vx I get 9.818181V.[/B]
You've got a sign error. The component of Vx produced by the 40 volt source is -80/11, not +80/11.
I am confused with the question it falls under the topic of Rectifier meter,
I feel the peak of the sine input need to be provided to calculate the full scale reading of the meter, 1mA is the resolution of the meter. Any hint to solve this problem?
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