Superposition in separation method of variables

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Homework Help Overview

The discussion revolves around the application of superposition in solving problems related to boundary conditions in electrostatics, particularly using the method of separation of variables. Participants explore how different charge configurations affect the solutions to the potential function.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the implications of different boundary conditions and their relation to charge configurations. Questions arise about the validity of using superposition in this context and the relationship between potential solutions at different boundaries.

Discussion Status

The discussion is ongoing, with participants questioning assumptions and exploring various interpretations of the problem. Some guidance has been offered regarding the relationship between potential functions, but there is no explicit consensus on the approach to take.

Contextual Notes

There is an indication that the exercise text may contain specific instructions that influence the discussion. Participants are cautious about assuming the problem's requirements and are aware of the need for a formal answer.

Celso
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Homework Statement
In a cube, the specified boundary counditions are V = ##V_{0}## in the ##z = 0## and ##z = d## planes and ##V = 0## for the other sides. Knowing the solution for when only one of the z planes is kept at ##V = V_{0}## how is it possible to use superposition to know ##V(r)## in this situation?
Relevant Equations
##\nabla^2 V = 0##
Each different boundary condition means a different charge configuration, how can this problem be solved using superposition?
 
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Seems very unlikely to me. Anyone says it can be ?
 
Let ##\Phi_0(x,y,z)## = solution when only the face at z = 0 is at ##V_0##.
Let ##\Phi_d(x,y,z)## = solution when only the face at z = d is at ##V_0##.
Assuming that the side of the cube is ##d##, isn't it true that ##\Phi_d(x,y,z)=\Phi_0(x,y,d-z)##?
 
Can you create a square pulse using two step functions? That is the crux of the question. I won't give the answer, as it is homework.
 
BvU said:
Seems very unlikely to me. Anyone says it can be ?
Ah! I get it: the exercise text as it was given to you says so o:) . Then it is most likely true, hmm ?
And @kuruman is giving you (much) more than just a hint !
 
BvU said:
Ah! I get it: the exercise text as it was given to you says so o:) . Then it is most likely true, hmm ?
And @kuruman is giving you (much) more than just a hint !
It's easy to assume that the problem is asking for the solution. Perhaps I was overly generous when I posted but I wanted to point OP in the right direction and there is still quite a bit to be said to complete a formal answer.
 
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