Surface charge density of a conducting spherical shell

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The discussion centers on the surface charge density of a conducting spherical shell, specifically the relationship σ = ϵ0 * E, where E is the electric field just outside the shell. Participants explain that applying Gauss's law with a Gaussian surface just outside the shell leads to an equation connecting E and σ. By taking the limit as the radius approaches the surface, the textbook's equation is validated. The formula holds true for conductive surfaces of any shape. The explanation clarifies the underlying physics without being homework-related.
Samanko
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The textbook says
' A conducting sphere shell with radius R is charged until the magnitude of the electric field just outside its surface is E. Then the surface charge density is σ = ϵ0 * E. '

The textbook does show why. Can anybody explain for me?
 
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Is this homework?

In any case apply Gauss's law with gaussian surface a sphere that has the same center as the charged sphere and radius ##R+dr## where ##dr## infinitesimal. You should get as result an equation that relates E (the electric field at distance R+dr) and ##\sigma## and ##R+dr##. Take the limit of that equation as ##dr\to 0## and you end up with the equation displayed in your textbook.
 
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Equation σ = ϵ0 * E applies to conductive surfaces, regardless of their shapes

E-Field 1.jpg
 
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Delta2 said:
Is this homework?

In any case apply Gauss's law with gaussian surface a sphere that has the same center as the charged sphere and radius ##R+dr## where ##dr## infinitesimal. You should get as result an equation that relates E (the electric field at distance R+dr) and ##\sigma## and ##R+dr##. Take the limit of that equation as ##dr\to 0## and you end up with the equation displayed in your textbook.
Got it! Thanks.
 
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