Surface charge density of a conducting spherical shell

Click For Summary
SUMMARY

The surface charge density (σ) of a conducting spherical shell can be calculated using the formula σ = ϵ0 * E, where E is the electric field just outside the surface. This relationship is derived using Gauss's law by considering a Gaussian surface with radius R + dr, where dr is an infinitesimal distance. As dr approaches zero, the equation simplifies to the textbook formula. This principle applies universally to conductive surfaces, irrespective of their shape.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with electric fields and surface charge density
  • Knowledge of the permittivity of free space (ϵ0)
  • Basic calculus for limits and infinitesimals
NEXT STEPS
  • Study the derivation of Gauss's Law in electrostatics
  • Explore the concept of electric fields around different geometries
  • Learn about the properties of conductive materials in electrostatics
  • Investigate applications of surface charge density in real-world scenarios
USEFUL FOR

Students of physics, electrical engineers, and anyone studying electrostatics or conductive materials will benefit from this discussion.

Samanko
Messages
14
Reaction score
3
The textbook says
' A conducting sphere shell with radius R is charged until the magnitude of the electric field just outside its surface is E. Then the surface charge density is σ = ϵ0 * E. '

The textbook does show why. Can anybody explain for me?
 
Physics news on Phys.org
Is this homework?

In any case apply Gauss's law with gaussian surface a sphere that has the same center as the charged sphere and radius ##R+dr## where ##dr## infinitesimal. You should get as result an equation that relates E (the electric field at distance R+dr) and ##\sigma## and ##R+dr##. Take the limit of that equation as ##dr\to 0## and you end up with the equation displayed in your textbook.
 
  • Informative
  • Like
Likes   Reactions: Samanko and Dale
Equation σ = ϵ0 * E applies to conductive surfaces, regardless of their shapes

E-Field 1.jpg
 
  • Like
Likes   Reactions: Samanko
Delta2 said:
Is this homework?

In any case apply Gauss's law with gaussian surface a sphere that has the same center as the charged sphere and radius ##R+dr## where ##dr## infinitesimal. You should get as result an equation that relates E (the electric field at distance R+dr) and ##\sigma## and ##R+dr##. Take the limit of that equation as ##dr\to 0## and you end up with the equation displayed in your textbook.
Got it! Thanks.
 
  • Like
Likes   Reactions: Delta2

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 24 ·
Replies
24
Views
8K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K