Surjective, injective and predicate

Click For Summary
SUMMARY

This discussion focuses on the definitions and checks for surjective and injective functions, specifically in the context of finite sets. To determine if a function f: A -> B is surjective, one must show that for every y in B, there exists an x in A such that f(x) = y. Conversely, to prove injectivity, it must be shown that if f(x1) = f(x2) for x1, x2 in A, then x1 must equal x2. The conversation also touches on the concept of predicates as characteristic functions of sets, although the term "predicate" is not universally recognized in this context.

PREREQUISITES
  • Understanding of surjective and injective functions
  • Familiarity with finite sets and their properties
  • Knowledge of mathematical symbols and quantifiers
  • Basic concepts of characteristic functions
NEXT STEPS
  • Study the definitions and properties of surjective and injective functions in detail
  • Learn how to express mathematical statements using quantifiers and logical operators
  • Explore the implications of combining surjective functions, particularly in the context of addition
  • Investigate characteristic functions and their applications in set theory
USEFUL FOR

Students of mathematics, particularly those studying calculus and set theory, as well as educators seeking to clarify concepts of function types and their properties.

reven
Messages
1
Reaction score
0

Homework Statement



How do I check if my function is surjective?

How do I check if my function is injective?

Suppose my function is a predicate and hence characteristic function of some set. How do I determine such a set?

Homework Equations



Does anyone know to write "The function f: A->B is not surjective? and The function f:A-> B is not injective?" in SYMBOLS using quantifiers and operators.

The Attempt at a Solution



If I have two finite sets, and a function between them. I can compute the value of the function at each point of its domain, I can count and compare sets elements, but I don't know how to do anything else.
I need detailed, explicit instructions for answering the questions IN WORDS. Can anyone help me to solve this problem.

Cheers mate
 
Last edited:
Physics news on Phys.org
reven said:

Homework Statement



How do I check if my function is surjective?

How do I check if my function is injective?
By showing that the definitions of "surjective" and "injective" hold, of course. For example, to show that a function, f, from A to B, is surjective, you must show that, if y is any member of B, then there exist x in A so that f(x)= y. To show that a function, f, from A to B, is injective, you must show that if f(x1)= y and f(x2)= y, where x1 and x2 are members of A and y is a member of B, then x1= x2.

Suppose my function is a predicate and hence characteristic function of some set. How do I determine such a set?
Sorry, I don't recognize the term "predicate" as applied to functions.

Homework Equations



Does anyone know to write "The function f: A->B is not surjective? and The function f:A-> B is not injective?" in SYMBOLS using quantifiers and operators.
I would say that "f is not surjective" means "There exist y in B such that, for all x in X, it is not true that f(x)= y" and "f is not injective" means "for all y in B, if there exist x1 in X such that f(x1)= y and there exist x2 in X such that f(x2)= y, then x1= x2."

The Attempt at a Solution



If I have two finite sets, and a function between them. I can compute the value of the function at each point of its domain, I can count and compare sets elements, but I don't know how to do anything else.
I need detailed, explicit instructions for answering the questions IN WORDS. Can anyone help me to solve this problem.

Cheers mate
You need to know the DEFINITIONS of "injective" and "surjective"!
 
I was wondering, if f: R -> R is surjective and g: R -> R is surjective, then is f + g also surjective? Intuitively the answer seems to be yes, and I can't think of any counterexamples. Perhaps I'm not thinking hard enough.
 
snipez90 said:
I was wondering, if f: R -> R is surjective and g: R -> R is surjective, then is f + g also surjective? Intuitively the answer seems to be yes, and I can't think of any counterexamples. Perhaps I'm not thinking hard enough.

f(x)=x is surjective (and injective), g(x)=-x is also surjective (and injective), what is the sum of f and g?
 
Ah, okay, thanks. These questions come up so often in my theoretical calc class and they often amount to using the additive and multiplicative inverses for counter examples. I need to keep that in mind.
 

Similar threads

Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K