System of diff eqs modeling salt in tanks

nate9519
Messages
47
Reaction score
0
1. The problem

dA/dt = -.02A
dB/dt = .01A - .04B
dC/dt = .01A + .04B

A(0)=1000
B(0)=0
C(0)=0Come up with a sketch and a word problem involving three tanks for which the system of differential equations with initial conditions above applies. Have fresh water flowing into tank A, with the volumes of brine in B and C remaining constant. Assume that the third tank has such capacity that it would not overflow during the time period under consideration. Use different values for the amounts of brine in tanks B and C (for example 1,000 gallons in tank B and 2,000 gallons in tank C [PS : don't use 1000 and 2000])

2. equations
n/a

3. Attempt at solution

Can someone help me interpret this problem. there are multiple aspects of this system that don't make sense to me. first is that if A flows into B then the rate out of A should be equal to the rate in for B. but instead it is half (.02A in dA/dt and .01A in dB/dt). and I also don't understand why dC/dt is a sum instead of a difference. If rate of change is rate in minus rate out then why is dC/dt a sum?
 
Physics news on Phys.org
nate9519 said:
1. The problem

dA/dt = -.02A
dB/dt = .01A - .04B
dC/dt = .01A + .04B

A(0)=1000
B(0)=0
C(0)=0Come up with a sketch and a word problem involving three tanks for which the system of differential equations with initial conditions above applies. Have fresh water flowing into tank A, with the volumes of brine in B and C remaining constant. Assume that the third tank has such capacity that it would not overflow during the time period under consideration. Use different values for the amounts of brine in tanks B and C (for example 1,000 gallons in tank B and 2,000 gallons in tank C [PS : don't use 1000 and 2000])

2. equations
n/a

3. Attempt at solution

Can someone help me interpret this problem. there are multiple aspects of this system that don't make sense to me. first is that if A flows into B then the rate out of A should be equal to the rate in for B. but instead it is half (.02A in dA/dt and .01A in dB/dt). and I also don't understand why dC/dt is a sum instead of a difference. If rate of change is rate in minus rate out then why is dC/dt a sum?

Think about the possibility that A flows into both B and C. What else must flow into C? And who said C has any outflow at all?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top