T = mgcosQHow is tension related to circular motion in a vertical circle?

[joemama69]

Homework Statement

A rock is whirled at the end of a rope in a vertical circle

Find a general expression fo the Tension

What is the magnitude of the total acceleration

Homework Equations

The Attempt at a Solution

\sumF_r = ma = T + mgcos\theta

T = ma - mgcos\theta not sure

a = (T + mgcos\theta)/m not sure

 

[rock.freak667]

At an angle θ to the vertical, what is the component of the weight along the line of tension?

 

[joemama69]

not sure what u mean

 

[rock.freak667]

not sure what u mean

Draw the mass at angle θ to the vertical.


Can you split the weight mg into two components?

 

[joemama69]

into two components, would that be the tangental compenent in the direction of the velocity and the second pointing towards teh center

 

[rock.freak667]

into two components, would that be the tangental compenent in the direction of the velocity and the second pointing towards teh center

actually it points opposite to the velocity and away from the center. What are these two components in terms of the angle?

 

[joemama69]

Component along line of tension ma = mgcosQ

how do i do tat for the velocity, do i integrate that

 

[rock.freak667]

Component along line of tension ma = mgcosQ

how do i do tat for the velocity, do i integrate that

the component is mgcosθ.

So the T points towards the center and the mgcosθ points away from the center. What is the resultant force equal to ?

 

[joemama69]

Fr = T - mgcosQ = 0