T to ∏ Conversion | Solve Homework Statement

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The discussion centers on performing a T to π conversion for a circuit problem involving impedances marked with an asterisk. The initial confusion arises from the representation of impedances as 2Z and the need for clarity on units, which are assumed to be ohms. Participants clarify the use of Wye to Delta conversion formulas, suggesting that the impedances can be substituted directly into the equations. The calculations for Rab, Rbc, and Rac are discussed, leading to values of 2.5Z and 5Z, indicating progress in solving the conversion. Overall, the conversation emphasizes understanding the conversion process and correctly applying the formulas to achieve the desired results.
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Homework Statement


Perform a T to ∏ conversion on the components marked with an asterix (see attachment)


The Attempt at a Solution



I believe the answer is 6.

Zab = sum of the two impedances connected to terminals "A and B"
+ product of T impedance connected to terminals "A and B"/third impedance

my issue is what should the units be as no units are apparent in the question simply ohms?

Or have I maybe misunderstood this process altogether?

As always any help is appreciated.
 

Attachments

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It's obviously not a pure number like "6".

Look for T - pi conversion methods in your textbook or on the Web.
 
I think my issue is three starting values the resistors are indicated by 2Z do i need to convert impedance first?
 
eddievic said:
I think my issue is three starting values the resistors are indicated by 2Z do i need to convert impedance first?
so i found the correct way to convert as per the attachment.

but I am still confused by the initial values being 2Z?
 

Attachments

Please include the diagram showing the various resistors in your attachment.
 
Its the first attachment listed as question 2
 
T as in Tao is 2Pi (I'm on tapatalk so if you put math symbols I only see plain text) Tao represents a full unit circle where as Pi is half.
 
eddievic said:
Its the first attachment listed as question 2

I meant the one that went along with the T to pi.docx.
 
rude man said:
I meant the one that went along with the T to pi.docx.

There is an attachment entitled question 2 that shows the questions diagram
 
  • #10
eddievic said:
There is an attachment entitled question 2 that shows the questions diagram

That's not what I meant
I need a pictorial showing how the R's are distributed. Not the Z's of the problem,.
 
  • #11
rude man said:
That's not what I meant
I need a pictorial showing how the R's are distributed. Not the Z's of the problem,.

Thats the only diagram provided with the question
 
  • #12
Never mind the question. What diagram went along with the T to pi.docx file?
 
  • #13
rude man said:
Never mind the question. What diagram went along with the T to pi.docx file?

I've now included the full question I'm working on exactly as it appears. Hopefully this explains all :)
 
  • #14
eddievic said:
I've now included the full question I'm working on exactly as it appears. Hopefully this explains all :)

its entitled Doc1.docx
 

Attachments

  • #15
eddievic said:
so i found the correct way to convert as per the attachment.

but I am still confused by the initial values being 2Z?

What is question 1? You're supposed to use the result from that to help with the final question.

There are 3 impedances marked with a "*". Let the top left one be Ra in the Wye to Delta formulas. Let the top right one be Rb and the middle impedance be Rc.

The 2Z designation need not be a problem. Simply replace Ra with 2Z, Rb with 2Z and Rc with Z in the formulas. What do you get for Rab when you do that? Then for Rbc and Rac?

Once you do all that, you should be able to get Vout or Zout by combining various series and parallel combinations, and using voltage divider formulas, etc.

Give it a try and show your work.

Once you have Rth (which will be an impedance and not a pure resistance for part c. of problem 2) you can use the maximum power transfer theorem to determine the load for maximum power out.
 
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  • #16
The Electrician said:
What is question 1? You're supposed to use the result from that to help with the final question.

There are 3 impedances marked with a "*". Let the top left one be Ra in the Wye to Delta formulas. Let the top right one be Rb and the middle impedance be Rc.

The 2Z designation need not be a problem. Simply replace Ra with 2Z, Rb with 2Z and Rc with Z in the formulas. What do you get for Rab when you do that? Then for Rbc and Rac?

Once you do all that, you should be able to get Vout or Zout by combining various series and parallel combinations, and using voltage divider formulas, etc.

Give it a try and show your work.

Once you have Rth (which will be an impedance and not a pure resistance for part c. of problem 2) you can use the maximum power transfer theorem to determine the load for maximum power out.

so T to ∏ conversion:

Rab = Ra x Rb + Ra x Rc + Rb x Rc / Rc
so z x z +z x 2z + z x 2z / 2z
= 2.5 z

so Rbc = 5z
Rac = 5z

is this along the right track?
 
  • #17
OK so far.
 

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