- #1
phillyolly
- 157
- 0
Homework Statement
6x/(x2+3)2
The Attempt at a Solution
If I solve this function as a multiplication, i.e.
6x (x2+3)-2
my answer is
f ' (x)=[ (x-3)(x-1) ]/(x2+3)3
If I solve it as a fraction
f ' (x)=(v'g-g'v)/g2
I get
f ' (x)=(x2-1)/(x2+3)3
This is all so confusing. Please help me out. Thank you.