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Taking basic integrals

  1. Oct 10, 2011 #1

    s7b

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    Its been a while since I took calculus so I'm confused as how to solve this.

    I've gotten my equation simplified as far as

    BdT=KdP and I'm supposed to solve for dP

    I do it and end up with B(T2-T1) = K(P2-P1)
    but this is giving me the wrong answer when I put the values in...

    What am I doing wrong?
     
  2. jcsd
  3. Oct 10, 2011 #2
    [tex] \int B dT = \int k \text{dP} \rightarrow BT + C_1 = kP + C_2[/tex]
    combine [tex]C= C_1 -C_2[/tex]
    [tex] \frac{BT + C}{k} = P [/tex]
     
  4. Oct 10, 2011 #3

    s7b

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    How are you supposed to solve something like that not knowing what C is though?
     
  5. Oct 10, 2011 #4
    P is a function of T
    [tex] P(T) [/tex]
    suppose you have a value of P(0) then to solve for C
    T=0
    [tex] P(0) = \frac{C}{k} [/tex]

    therefore,
    [tex] P(T) = \frac{B}{k} T + P(0) = \frac{B}{k} T + \frac{C}{k} [/tex]
     
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