Tangent/Normal with derivative

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Homework Statement


Find the lines that are (a) tangent and (b) normal to the curve y=x3 at the point (1,1).

Homework Equations


The Attempt at a Solution


So first I found the derivative, 3x2. Then I used x=1 to find the slope which is 3.

(a)y-1=3(x-1)
y=3x-2

(b)y-1=(-1/3)(x-1)
y=(-1/3)x+(4/3)Not really sure if I found the slope correctly tho..
 
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It looks good to me.

If two lines are perpendicular, then the product of their slopes is -1 .
 
Looks good to me. I see no problem with a or b.
 
Thanks :p
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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