- #1
Roq
- 15
- 0
Hello, I'm having problem finding tangential acceleration. I was trying to find some examples of this being done in my book and on the web, but I couldn't. So I hope someone can help me with this.
The problem is: "A point on a rotating turntable 20.0cm from the center accelerates from rest to a speed of 0.700 m/s in 1.75s. At t=1.25s, find the magnitude and direction of (a) the radial acceleration, (b) the tangential acceleration, and (c) the total acceleration of the point."
The book as only covered uniform acceleration at this point, so I assumed it was here although it did not say.
For part (a), to try and find the acceleration I did: .7m/1.75, and multiplied it by 1.25 to get the velocity at the time, getting .5 m/s. I divided -.5^2 by .2 (20 cm converted to m), getting -1.25 m/s^2. It asked for the direction, and I think the direction is given by the minus sign, indicating it is towards the center.
I am stuck on part (b). The formula for tangential acceleration is d|v|/dt, but I am unsure what formula that I have for velocity. In this case,
v = acceleration * time = 0.4m/s^2(t). So if I derived that I would get .4m/s^2. Is this the answer?
The problem is: "A point on a rotating turntable 20.0cm from the center accelerates from rest to a speed of 0.700 m/s in 1.75s. At t=1.25s, find the magnitude and direction of (a) the radial acceleration, (b) the tangential acceleration, and (c) the total acceleration of the point."
The book as only covered uniform acceleration at this point, so I assumed it was here although it did not say.
For part (a), to try and find the acceleration I did: .7m/1.75, and multiplied it by 1.25 to get the velocity at the time, getting .5 m/s. I divided -.5^2 by .2 (20 cm converted to m), getting -1.25 m/s^2. It asked for the direction, and I think the direction is given by the minus sign, indicating it is towards the center.
I am stuck on part (b). The formula for tangential acceleration is d|v|/dt, but I am unsure what formula that I have for velocity. In this case,
v = acceleration * time = 0.4m/s^2(t). So if I derived that I would get .4m/s^2. Is this the answer?