Tarzan, Fluids, and Pressure

  • #1
Ape Man in a movie is shown evading his captors by hiding underwater for many minutes while breathing through a long reed. Assuming the maximum pressure difference lungs can manage and still breathe is -80 mm-Hg , calculate the deepest he could have been.

I immediately thought of P = p*g*h, where p = density. h is the depth, but this is for gauge pressure. Do I use the formula for absolute pressure P = atmospheric pressure + pgh?

Am I correct in my reasoning?

Thanks.
 

Answers and Replies

  • #2
609
0
First... you have to make an assumtion that the lung won't be compress under water, otherwise the problem can't be solve this way.
Yes the absolute pressure under water is [itex] \rho g h + 1atm [/itex]... however, the pressure inside the (uncompressed) lung is 1atm... so the DIFFERENT of the pressue is [itex] \rho g h[/itex]
 

Related Threads on Tarzan, Fluids, and Pressure

  • Last Post
Replies
10
Views
9K
  • Last Post
Replies
4
Views
10K
  • Last Post
Replies
12
Views
4K
  • Last Post
Replies
3
Views
645
  • Last Post
Replies
7
Views
14K
  • Last Post
Replies
7
Views
2K
  • Last Post
2
Replies
46
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
3
Views
7K
  • Last Post
Replies
5
Views
3K
Top