Tau and phi (conjugates?) fibonacci sequence

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SUMMARY

Tau (τ) and phi (φ) are indeed considered conjugates in the context of the Fibonacci sequence, where τ = (1 - √5)/2 and φ = (1 + √5)/2. The product of τ and φ results in a real number without square roots, similar to the multiplication of complex conjugates. This property aids in understanding the Binet formula, which expresses Fibonacci numbers using these constants.

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  • Familiarity with complex numbers and their conjugates
  • Basic algebraic manipulation involving square roots
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Homework Statement


Would tau and phi be considered conjugates?

Homework Equations


[itex]\tau[/itex] = [itex]\frac{1-\sqrt{5}}{2}[/itex]
[itex]\phi[/itex] = [itex]\frac{1+\sqrt{5}}{2}[/itex]

The Attempt at a Solution


I know that a complex number such as 1+2i would have 1-2i as a conjugate. However, for fractions, I can't quite remember if the same rule applies.

Thank you in advance
 
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yes, the reason is tau x phi will give a results with not square roots in the expression

similarly for complex numbers, the result of multiplying conjugates is real
 
lanedance said:
yes, the reason is tau x phi will give a results with not square roots in the expression

similarly for complex numbers, the result of multiplying conjugates is real

Thank you! This will help me better understand the binet formula :biggrin:
 

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