Taylor Polynomial for f(x)=ln3x

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Homework Statement


Find the Taylor Polynomial of degree 3 for the function f(x) = ln3x about a = 1/3

Homework Equations


None

The Attempt at a Solution


I have found up to the fourth derivative of f(x) along with the values of the derivatives at x = 1/3.

At this point i get Σ{(-1)kk!fk(1/3)}, but am unsure of whether or not this is correct or if I am missing something. Also, not sure of what should go on top of an below the summation symbol...I think its 4 and k=0.

Thanks for your help.
 
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Nick_273 said:

Homework Statement


Find the Taylor Polynomial of degree 3 for the function f(x) = ln3x about a = 1/3


Homework Equations


None


The Attempt at a Solution


I have found up to the fourth derivative of f(x) along with the values of the derivatives at x = 1/3.

At this point i get Σ{(-1)kk!fk(1/3)}, but am unsure of whether or not this is correct or if I am missing something. Also, not sure of what should go on top of an below the summation symbol...I think its 4 and k=0.

Thanks for your help.

I think the taylor polynomial should be a polynomial. That doesn't look like a polynomial to me.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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