# Taylor series

Find P5(x), the 5th order Taylor series, of sin (x) about x = 0. Hence find the 4th
order Taylor series for x sin (2x) about x = 0.

In this question why is it required to find the 5th order taylor series of sin(x) to find the 4th order taylor series of xsin(2x)?

Mark44
Mentor
After you have P5(x), it's a simple matter to find the power series for xsin(2x). "Hence" in this problem just means "after that," I believe.

HallsofIvy