Tension at an angle from hanging mass

AI Thread Summary
The discussion revolves around calculating the tension in a cable connected to a mass, with emphasis on understanding the forces involved. The tension is proposed to be 800N, using 10 m/s² for gravitational acceleration. Participants suggest drawing a free body diagram to visualize the forces, including tension, weight, and the force exerted by the bar. The mass is in equilibrium, indicating that the forces in both horizontal and vertical directions must balance. The approach to solving for tension is confirmed as straightforward, emphasizing the importance of analyzing the forces correctly.
austindubose
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I apologize for my multiple recent posts, but I'm having pre-exam stress, so even the simplest things seem nearly impossible. Haha..

Homework Statement


2pycaqg.png

Note that connection point between the bar and the cable is not a pulley.


Homework Equations


F=ma


The Attempt at a Solution


The problem seems to be pretty straightforward, but would T=800N? (We use 10 m/s2 for acceleration due to gravity.) And also, what would clue me into whether the bar pushes or pulls on the ropes?

Thanks!
 
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Draw a free body diagram of the hanging mass. You should have the tension, weight, and force the bar exerts. Split the tension into horizontal and vertical components.

The mass is in equilibrium so the left/right and up/down forces must be equal that should clue you in as to what direction the bar force is exerting.

It should be pretty straight forward to solve for tension now also.
 
Sorry for the late reply, but would this be the correct way to approach this?
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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