Tension downward acceleration problems

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving tension in a system of masses connected by pulleys, where the entire system is accelerating downwards at a rate of g/2. Participants are attempting to determine the tensions T1 and T2 using the masses m1, m2, and gravitational acceleration g.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss drawing free body diagrams (FBDs) for the masses to analyze forces. Some express uncertainty about how to relate the forces when the system is accelerating. Others question their assumptions about the system's movement and the effects of the masses on the pulleys.

Discussion Status

There is ongoing exploration of the problem, with some participants sharing their reasoning and attempts at setting up equations. Guidance has been offered to draw FBDs and consider the relationships between the tensions and the masses. Multiple interpretations of the system's behavior are being examined, but no consensus has been reached.

Contextual Notes

Participants mention assumptions such as massless and frictionless pulleys, and there is some confusion regarding whether the system is in motion or at rest, which affects their analysis.

dkgojackets
Messages
38
Reaction score
0
phys.jpg


Im supposed to find T1 and T2 using m1, m2, and g. The whole system is accelerating downwards with magnitude g/2.

Maybe if I get this I can figure out the more complex ones. Thanks.
 
Physics news on Phys.org
dkgojackets said:
phys.jpg


Im supposed to find T1 and T2 using m1, m2, and g. The whole system is accelerating downwards with magnitude g/2.

Maybe if I get this I can figure out the more complex ones. Thanks.
Draw free body diagrams for both the masses and see if you can work it out. We will help you if you show us your attempt.
 
Its tough to put in paint, but for m1 I have T1 going up, T2 going down, and .5(m1)g going down. On m2 I have T2 up and .5(m2)g down.

Looking at m2, I have the sum of forces being T2 - .5(m2)g

I'm not used to having the system accelerate, but right now I can only think of making T2 = .5(m2)g. T1 would be .5(m1 + m2)g then. I just don't think that is correct.
 
Nevermind, it is :)
 
OK here's the one I am really stuck on. I am just not completely sure what's going on. I'm looking for T. The units are kg for mass of the blocks, and I am assuming massless/frictionless pulleys.

threepulley.jpg


I drew the FBD for each mass, I am just not sure how to connect it all.
 
So far I am thinking about trying to balance the force on each side of that middle pulley. I have the total mass on the right side that its carrying as 7+2.5? (since half of that 5 is attached the the "floor".) For the left side, I am thinking the mass there now is .5 (half of the 1 is attached to the "ceiling", so I need to get another 9 kgs (and 9 x 9.8 = 88.2 N as T).

Is this completely wrong thinking?
 
dkgojackets said:
OK here's the one I am really stuck on. I am just not completely sure what's going on. I'm looking for T. The units are kg for mass of the blocks, and I am assuming massless/frictionless pulleys.
You have two strings and therefore two tensions. You need to know how far each mass moves in relation to the other masses. With that information, your FBDs should get you a solvable system of equations.
 
Still stuck. I think I am missing the effect that the masses have when they are attached to the pulley, not the actual string.
 
dkgojackets said:
Still stuck. I think I am missing the effect that the masses have when they are attached to the pulley, not the actual string.
I think I misinterpreted the problem. Nothing is moving here? Is that correct?

It is so frustrating when this system freezes up like this. I’ve been frozen out for a long time.
In case I cannot get back in, here is what I have assuming nothing is moving.

TL is the tension in the upper left string
TR is the tension in the lower right string.

T + 1kg*g = 2TL
TL = 7kg*g + 2TR
TR = 5kg*g
 
Last edited:
  • #10
Thank you. That makes sense now.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 102 ·
4
Replies
102
Views
9K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
2
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
5K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 52 ·
2
Replies
52
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K