What is the 'spring' constant of a bungee cord?

  • Thread starter Thread starter sunniexdayzz
  • Start date Start date
  • Tags Tags
    Bungee Tension
sunniexdayzz
Messages
13
Reaction score
0

Homework Statement



Consider a bungee cord of unstretched length L0 = 43 m. When the cord is stretched to L > L0 it behaves like a spring and its tension follows the Hooke’s law T = k(L − L0). But unlike a spring, the cord folds instead of becoming compressed when the distance between its ends is less than the unstretched length: For L < L0 the cord has zero tension and zero elastic energy. To test the cord’s reliability, one end is tied to a high bridge (height H = 147 m above the surface of a river) and the other end is tied to a steel ball of weight mg = 120 kg×9.8 m/s2. The ball is dropped off the bridge with zero initial speed. Fortunately, the cord works and the ball stops in the air 14 m above the water — and then the cord pulls it back up. Calculate the cord’s ‘spring’ constant k. For simplicity, neglects the cord’s own weight and inertia as well as the air drag on the ball and the cord. Answer in units of N/m.

Homework Equations


F=ma
T=k(L-L0)
gravity = 9.8m/s^2


The Attempt at a Solution


I tried to figure out the Tension by using f=ma
I assumed that acceleration at the bottom of the rope was 0 .. but now thinking about it i don't think that's true. so then if T is tension and G is the mass x gravity then T + G = ma

then i would plug in T for hooke's law and solve for k.

I guess my biggest problem is figuring out what T is.
 
Physics news on Phys.org
This is a dynamics problem, so you better treat it as such.

Consider the motion in two phases.
Phase 1: There is no tension in the cord, the ball has not fallen far enough to pull the cord tight.
Phase 2: The ball is continuing to fall, with the cord acting like a spring.

Solve the first phase, and find out the time when the first phase ends, the position and velocity at that time. These become the initial conditions for the second phase.

Solve the second phase, using the terminal conditions from the first phase as initial conditions. Carry the solution to the max displacement which was a given value. Use this to evaluate your final constants.

Now you should be able to back out the required value for the spring constant.

It is just a little bit more than simple plug and chug!
 
thank you for your help!

i figured out phase 1, but i am not sure about phase 2. i tried using conservation of energy from when the tension begins to the final length of the cord, using final kinetic energy + final potential energy = initial potential energy + initial kinetic energy and solving for k .. but I'm not getting the right answer .. do u have any suggestions?
 
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top