Tension in and out of water in constant velocity

AI Thread Summary
The discussion focuses on calculating the tension in a crane's cable while lifting an 18,000-kg steel hull of a ship at constant velocity, both submerged and out of water. For part A, the tension when submerged involves considering the buoyant force due to the displaced water, while part B requires understanding that the tension is equal to the weight of the hull when it is fully out of the water. There is confusion regarding the calculations, particularly about how to determine the water displaced when submerged. Participants agree on the need to account for buoyancy in the submerged scenario and confirm the calculations for both parts. Accurate understanding of these principles is crucial for solving the problem correctly.
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A crane lifts the 18,000-kg steel hull of a ship out of the water at constant velocity.

(A) Determine the tension in the crane’s cable when the hull is submerged in the water.

(B) Find the tension when the hull is completely out of the water.

I would have thought that B would just be the weight, but apparently that was wrong. And how do you find the amount of water displaced when the hull is submerged? I was thinking maybe A is the weight minus the displacement?

Thanks in advance for any help!
 
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Your answer to B looks right to me. What's your reason for saying it's wrong?
I agree with your answer to A too.
 

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