Tension in Cord: Same or Different?

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The tension in the cord connecting multiple masses will not be the same throughout the system, despite the cord being massless and the masses being equal. Each segment of the cord experiences different tensions due to the presence of the masses, which must be treated as independent segments. While it may be valid to consider the three masses as a single mass of 3m for certain calculations, this does not imply uniform tension across the cord. The tension varies depending on how many masses each segment of the cord is pulling. Understanding the distribution of forces through free body diagrams is essential for accurately determining the tension in each segment.
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Hi,
Will the tension in the cord attaching all masses (see diagram) be the same (one tension T for the entire system) or will there be different tensions? It is stated that the cord has no mass and the masses are all the same. Furthermore, may I consider the 3 masses lying on the horizontal surface as one mass of 3m?
 

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peripatein said:
Hi,
Will the tension in the cord attaching all masses (see diagram) be the same (one tension T for the entire system) or will there be different tensions?
What do you think? Since the masses are connect by the cord, what must be the same for each?
It is stated that the cord has no mass and the masses are all the same. Furthermore, may I consider the 3 masses lying on the horizontal surface as one mass of 3m?
Depending up what you are trying to find, you can treat any grouping of the masses as a single system. For some purposes you may want to consider the three masses as a single mass of 3m; for other purposes you may want to consider each mass separately. Up to you and what you need to solve for.
 
Will the tension in the cord attaching all masses (see diagram) be the same (one tension T for the entire system) or will there be different tensions?
Do the free body diagram for each mass. Look at the one for the mass on the table nearest the pulley. What does that tell you about the tensions?
may I consider the 3 masses lying on the horizontal surface as one mass of 3m?
It depends what you do with it. For some equations it would be valid.
 
I think the tension would be similar throughout the cord as it is a massless cord and one and the same. Am I wrong?
 
peripatein said:
I think the tension would be similar throughout the cord as it is a massless cord and one and the same. Am I wrong?
Yes, you are wrong. If the cord were not broken up by those masses and was one continuous piece, then you'd be correct. Since the segments are divided by masses, you must treat them as independent cords, each with its own tension.

Imagine you had to pull that chain of masses with some given acceleration. Would pulling three masses require the same force as pulling one?
 
But the masses are equal. Why can't I just regard it as a uniform mass of 3m?
 
peripatein said:
But the masses are equal. Why can't I just regard it as a uniform mass of 3m?
For some purposes, you can. (As I said earlier.) But that doesn't mean the tension in the cord segments are all the same.

What are you trying to determine?
 
The tension in the cord
 
peripatein said:
The tension in the cord
Which piece? All of them? They each will have a different tension.
 
  • #10
How many masses is the cord furthest to the left pulling? How many masses is the cord second furthest from the left pulling? How many masses is the cord third furthest from the left pulling?
 
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