Tension In musical strings and wavelength

AI Thread Summary
To determine the tension needed for a musical string to produce a wavelength of 3.39 cm in its second overtone, the correct approach involves using the wave speed on the string rather than the speed of sound in air. The linear density of the string is calculated using its mass and length, converting units appropriately. The frequency of the wave can be found using the equation v = f * λ, where v is the speed of sound in air. This frequency should then be applied to the equations governing the vibrating string to find the necessary tension. Properly distinguishing between the wave properties of the string and the sound in air is crucial for solving the problem accurately.
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Homework Statement



One string of a certain musical instrument is 79.0cm long and has a mass of 8.79g . It is being played in a room where the speed of sound is 344m/s .
A)To what tension must you adjust the string so that, when vibrating in its second overtone, it produces sound of wavelength 3.39cm ?
B)What frequency sound does this string produce in its fundamental mode of vibration?


Homework Equations


v=sqroot(Tension/linear density), linear Density=m/L, v=(f)(lamda)=(omega)/k, k=2(pi)/(lamda)


The Attempt at a Solution



I keep trying to get out a way to find T but always end up reducing an eqaution to something pointless such as f=f or (lamda)=(lamda). My real problem is a concept one...Is the v used in equations the speed of sound in the room (334m/s) and when finding linear density do I use .79m or .0339m as the length. Please respond..anything helps and thank you.
 
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The v must be the velocity of the wave on the string when referring to the wave on the string. But use 344 m/s for the sound "of wavelength 3.39 cm". Use 8.79g/79 cm (in standard units) for the linear density of the string.
 
I tried using 344m/s as the v in the eqaution v=sqroot(Tension/linear denstiy)

so... v^2 = Tension/Linear Density
so... Tension= v^2 (linear Density) => tension= (344m/s^2)(.00879kg/.79m)=1316.67N.
However when I tried that it was wrong. I am still confused about the "of wavelength 3.39cm" and the second overtone. Don't they need to come into the problem too? Thank you
 
I tried using 344m/s as the v in the eqaution v=sqroot(Tension/linear denstiy)

You are mixing the sound and the vibration on the string incorrectly.
The thing they have in common is the frequency. Use v = f*lambda for the sound with v=344 and lambda = .0339 to get the frequency for both the wave AND the vibration. Then use that frequency with formulas that apply to the vibrating string.
 
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