Tension in String: Solving 10kg Block Problem

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A 10 kg block is at rest on a frictionless surface, connected to a wall by a light inelastic string, with a 50 N force applied at a 30-degree angle. The initial assumption for the tension in the string was 25 N, calculated using the sine of 30 degrees. However, this calculation was deemed incorrect, prompting a discussion on the proper resolution of the horizontal and vertical components of the applied force. Participants emphasized the need to analyze these components to accurately determine the tension in the string. The resolution of this problem requires a deeper understanding of vector forces and their impact on the system.
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Homework Statement


A 10 kg block is at rest on a frictionless surface. The block is attached by a light inelastic string to a rigid wall. A force of 50 N is applied to the mass as shown in the diagram (attachment).

Homework Equations


The tension in the string is
a 148N
a 50N
c 43.3N
d 25N

The Attempt at a Solution


I think the tension on the string is 25N because sin30 is 0.5, and 0.5 x 50 = 25
 

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I can't see the diagram yet. Perhaps you could describe the diagram.
 
ride4life said:
I think the tension on the string is 25N because sin30 is 0.5, and 0.5 x 50 = 25
That's incorrect. What are the horizontal and vertical components of that 50 N force?
 
There's a 10kg blck at rest on a frictionless surface. On the left of it is a string attached to it which is attached to the rigid wall as well. On the right a force of 50N is applied to it at 30 degrees to the horizontal.
 
Last edited:
ride4life: I agree with Doc Al. Your current answer is incorrect.
 
adjacent
 
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