Tension on a Vertical Circle- Conceptual Question

AI Thread Summary
When a solid rubber ball is swung in a vertical circle, tension exists even when the ball is at the leftmost side of the circle. Although the velocity is directed downwards, the ball is still undergoing centripetal acceleration, which requires tension in the string to maintain circular motion. The net force equation can be applied to analyze the forces acting on the ball, including gravitational force and tension. It is important to recognize that acceleration can occur without a change in speed, as direction changes. Understanding these concepts is crucial for solving the problem accurately.
kmridgeway
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Homework Statement


GIVEN: mass = .34 kg
radius =.5 m

If a solid rubber ball attached to the end of a light string is swung at a constant speed in a vertical circle, what is the tension a quarter of the way around the circle (i.e. when the string attached to the ball is horizontal with the ground/ the ball is at the leftmost side of the circle) ?

My main question is a conceptual one; would there in fact be any tension exerted on the rubber ball? It seems at this point, since the velocity of the ball would be directly downwards, there would be no horizontal force (tension) exerted upon the ball to alter its course...

Is this correct? If so, how might I go about proving this?

Under normal circumstances (if the ball was at the top of the circle, for example) I would simply say that:
F (net force) = FG + T
F = mv2/R
mv2/R = FG + T
T = mv2/R - m*g

Thanks so much for any help!
 
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Well you are correct in saying that the tangential velocity at this point is directly downwards, however, have a think of where the acceleration is.

Hint; even if the magnitude of the velocity is not changing, the particle can still be accelerating.
 
oh of course! Thank you so much for your help :)
 
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