Tensions Equilibrium: Finding Unit Vectors

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To find the unit vector for force M, which has a magnitude of 20 kN and is directed at a 20-degree angle with the positive y-axis, trigonometric functions can be applied. The components of the vector can be calculated using the sine and cosine of the angle, considering that M is parallel to the x-y plane. The provided answer of 6.84i + 18.794j represents the correct unit vector for M. Understanding that a unit vector has a magnitude of 1 is crucial for this calculation. The discussion clarifies the method to derive the components from the diagram using trigonometry.
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Homework Statement


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Homework Equations


The Attempt at a Solution


Ive worked out T1 which is T1=F1(-4i-5j-10k/11.8743) = T1(-0.337i-0.421j-0.842k)
and T2=F2(-4i-5j-10k/11.8743) =T2(0.337i-0.421j-0.842k)
and the next step is to find the unit vector of force M = 20kn but how do i work out unit vectors from the diagram if the lengths aren't given?

(the answer given is 6.84i + 18.794j for the unit vector of M=20kN but how??)
 

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You obviously don't realize that a 'unit vector' has a magnitude = 1, which is why it's called a unit vector.

You know the magnitude of the force M (which = 20 kN) and you are shown the direction of the M vector in the diagram. The M-vector is parallel to the x-y plane and it makes an angle of 20 degrees with the positive y-axis. Ergo, you can work out the components of M using simple trigonometry.
 
oh i get it now thanks
 
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