(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

(a) Calculate the terminal speed of a wooden sphere(density .830 g/cm^3)

falling through the air if its radius is 8.00cm and its drag coefficient is .500.

(b) From what height would a freely falling object reach this speed in the

absence of air resistance?

2. Relevant equations

p =m/v

m=pv

Vt = sqrrt 2mg/DpA

3. The attempt at a solution

p = .830 g/cm3

r = 8.00 cm = .080m

A = pie(r2) = .020m2

D = .500

Volume of Sphere = 4/3 pie(r3) = .335m3

I have the Velocity equation ready to go but I don't think that I'm converting

p correctly. I get .830 g/cm3 = 8.3x10 -7 g/m3

I'm not sure how to go to kg/m3, which is what I believe that I need to find

speed since g = m/s2

Once I get p to be correct I can get m and p and put them into the Vt equation.

I think I'm confused on the conversion.

Thanks,

Kevin

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Terminal Speed and Height of Object

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