1. The problem statement, all variables and given/known data Here's the circuit in question http://s52.beta.photobucket.com/user/I_eat_corn/media/circuit1.png.html I need to calculate the voltage at terminals A, B, C, and D. (A and B are finished and checked) 2. Relevant equations Ohms Law, E=IR, I=E\R, R=E\I, P=VI or RI^2 3. The attempt at a solution Knowing that Vs = 10V, and Req = 21.5909Ω, I = 463.2mA I calculated A to be 10V (0.463mA x 21.5909Ω = 10V) B is 0.463mA x 11.5909Ω = 5.368V C is where things are getting tricky. I am stumbling with what exactly I'm supposed to do here as I've never encountered a circuit like this before (I'm obviously an amateur). I THINK that my calculations are going to be relative to how parallel branches R2 and (R3+R4) meet up and then pass through R5 to ground, considering how my reference point is ground. I have punched the circuit into my computer and ran a simulation, so I know what the answers are, I just cannot figure out how to get them. I double checked my points A and B and proved my answers to be correct, but I'm struggling with coming up with an answer for C. I think after C, D will be easy considering it will be an extension so to speak of C. Answers ahead of time: Voltage @ C: 4.105V, Amperage: 84.21mA Voltage @ D: 3.474V, Amperage: 84.21mA Voltage after R2: 3.474, Amperage is 378.9mA As for my own personal attempts: - I tried calculating voltage by removing R1 and R3 from the Req, so I have (1\5 + 1\7.5)^-1+7.5. That gave me 10.5ohms as my Req-R1-R3. I multiplied that by Voltage at B (5.368) -I tried just 5.368\((1\r4)^-1 + 7.5) that gave me an answer... closer... but not correct nevertheless... I'm pretty clueless now, I've made other attempts but cannot remember them off the top of my head.