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SolidSnake
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Homework Statement
Show that:
0 <= A <= B
[tex] A \leq \sqrt{AB} \leq (A + B)/ 2 \leq B [/tex]
Homework Equations
root AB = geometric mean
(A + B)/ 2 = arithmetic mean
<= means less then or equal to.
The Attempt at a Solution
I managed to come up with something for the (A + B)/ 2 part.
a < = (a+a)/2 <= (a+b)/2 <= (b+b)/2 <= b
that shows that (a+b)/2 is less then b but greater then a. i can't figure out how to show that with root ab.
Any help would be great!
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