IMO, the last paragraph in 256bits' post is the most important for getting an intuitive understanding as to the why. Let me repeat my elaboration on this topic from an earlier thread(
https://www.physicsforums.com/showthread.php?t=697273):
As far as the inverse sqare law goes, that's the result of the world being (spatially) three-dimensional.
It's easy to see why, when you begin by considering a source of whatever you want(e.g., radiation, force) in one-dimensional space.
So, we've got a line(1d space) with a point-like source located somewhere on it. The source is causing some sort of interaction to propagate from it in all directions. In 1d space, that means all the output is divided equally between the two directions. Whichever point on the line you choose, no matter how distant from the source, the strength of the interaction measured there will always be the same as at any other point, and equal to half the source strength. There's nowhere else for the interaction to dissipate but being split in half.
So in such a space, e.g. the gravitational force would not have \frac{1}{R^2} in it. It would have no R at all, as the strenght is distance independent.
Now let's take a 2d space(a plane). In this case, the interaction propagates in the form of expanding circles centered around the source. If you pick one point somewhere on the plane, you'll find out that the interaction has been spread thinner, as the same amount of it needs to cover more space. At any given distance R, there are 2\pi R points that equally share the original interaction between them. Since the interaction has to be divided between all the points on the circle with size dependent on an R variable, the force of gravity would have the factor \frac{1}{R} in it.
Three-dimensional space adds another dimension into which the interaction must spread, so that at any given distance R there is 4\pi R^2(concentric spheres) points sharing what the source had produced. Hence the \frac{1}{R^2} factor in the equations.