The average emf created by the earths magnetic field.

AI Thread Summary
The average electromotive force (emf) generated by a 15-turn cable with a diameter of 0.5 meters, flipped 180 degrees in 2 seconds, is calculated using the formula e = -n * r^2 * (delta B / delta T). Given the Earth's magnetic field of 0.5 micro Tesla, the change in magnetic flux (delta B) is 1 micro Tesla. Substituting the values, the calculated emf is approximately -0.468 micro Volts. An alternative calculation using the area of the cable also yields an emf of about 0.098 micro Volts. Both methods illustrate the relationship between magnetic fields and induced emf in a rotating conductor.
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Homework Statement


What is the average emf created by a 15 turn cable that is .5 meters in diameter, lies flat with the surface of the Earth and is flipped 180 degrees in 2 seconds?
*Assume the Earth produces a magnetic field of .5 micro Tesla.


Homework Equations



e=-n*r^2*delta B/delta T

The Attempt at a Solution



n=15
delta B=.5*10^-6 minus -.5*10^-6 =1*10^-6 Tesla.
Delta T= 2 seconds
r=.25

e=-.468 micro Volts?
 
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e=-π*r^2*delta B/delta T
= π*(.25)²*(1x10^-6)/2 = .098 x 10^-6
 
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