- #1
PineApple2
- 49
- 0
Hello. I read about the born series in scattering,
[tex]
|\psi> = (1+G_0V+\ldots)|\psi_0>
[/tex]
Now when I want to move to spatial representation, the textbook asserts I should get
[tex]
\psi(\vec{r})=\psi_0(\vec{r}) + \int dV' G_0(\vec{r},\vec{r'}) V(\vec{r'})\psi_0(\vec{r'})+\ldots
[/tex]
by operating with [itex]<\vec{r}|[/itex] from the left. However I don't know how to get the 2nd term (the integral). I tried to insert a complete basis like this:
[tex]
<\vec{r}|G_0V|\psi_0> = \int d^3r'<\vec{r}|G_0|\vec{r'}><\vec{r'}|V|\psi_0>
[/tex]
however I don't know how to get [itex]V(\vec{r'})[/itex] from the second bracketed term. Any help?
By the way: is there a "nicer" way to write 'bra' and 'ket' in this forum?
[tex]
|\psi> = (1+G_0V+\ldots)|\psi_0>
[/tex]
Now when I want to move to spatial representation, the textbook asserts I should get
[tex]
\psi(\vec{r})=\psi_0(\vec{r}) + \int dV' G_0(\vec{r},\vec{r'}) V(\vec{r'})\psi_0(\vec{r'})+\ldots
[/tex]
by operating with [itex]<\vec{r}|[/itex] from the left. However I don't know how to get the 2nd term (the integral). I tried to insert a complete basis like this:
[tex]
<\vec{r}|G_0V|\psi_0> = \int d^3r'<\vec{r}|G_0|\vec{r'}><\vec{r'}|V|\psi_0>
[/tex]
however I don't know how to get [itex]V(\vec{r'})[/itex] from the second bracketed term. Any help?
By the way: is there a "nicer" way to write 'bra' and 'ket' in this forum?
Last edited: