A The Compton Effect: Scattering Low Energy Photons by Electrons

  • A
  • Thread starter Thread starter Spar
  • Start date Start date
  • Tags Tags
    Compton effect
Spar
Messages
7
Reaction score
0
An electron which is freely propagating in space cannot absorb any photon. What if we scatter a low energy photon (big wavelength) by a free electron? Will it be the Compton scattering?
 
Physics news on Phys.org
Scattering high energy electrons on low energy photons is typically referred to as inverse Compton scattering and produces high energy photons.
 
  • Like
Likes Spar
Spar said:
An electron which is freely propagating in space cannot absorb any photon. What if we scatter a low energy photon (big wavelength) by a free electron? Will it be the Compton scattering?
Yes
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top