The Electric Field Above a Plane: Have I Made a Wrong Assumption?

AI Thread Summary
The discussion revolves around the confusion regarding the electric field above an infinite charged plane. It highlights the misconception that the electric field strength diminishes with distance, clarifying that for an infinite plane, the field remains uniform and does not depend on distance. The participant grapples with equations related to electric fields, particularly questioning the application of the formula E=kQ/r^2 in this context. They acknowledge the need to consider charge per unit area instead of total charge when analyzing the electric field. Ultimately, the conversation emphasizes the unique characteristics of electric fields generated by infinite planes compared to point charges or line charges.
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I'm a bit confused about the electric field above a plate. First, I have come across the equation E=kQ http://www.sparknotes.com/testprep/books/sat2/physics/chapter13section3.rhtml which in many ways makes sense to me because around a point the field would be proportional to 1/{r^2}, and then for a line it would be proportional to 1/{r} etc, however I have not come across this formula anywhere else and am finding it hard to understand why moving away from the plate would not have any impact at all on the strength of the force on a changed partcle. Also, if this were the case then I would expect the field between two parallel plates to be E=2kQ due to the principle of superposition. However I know from elsewhere that the E field between two parallel plates is E=V/d and for a capacitor C=Q/V, and in the case of just air between the plates, C=\epsilon A/d, so putting that together I get that E=kQ/r^2...

Have I made a wrong assumption somewhere?

Thank you!

EDIT: Sorry, for the last part I used A=4\pi r^2 which probably will not apply here. In that case, I am not sure what to do for the last part...
 
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The plate is a plane, extending out to infinity so there are no edge effects. The plane carries charge uniformly distributed. Field lines from these charges space themselves apart and never cross each other, so the only possible field lines arrangement is all perpendicular to the plane, like the hairs on the back of a frightened cat. These field lines extend out to infinity and remain parallel to each other. So no matter how far away from the plane, the field strength is uniform and undiminished.

Your equations were looking good until the last where r leapt in unheralded and uninvited!
 
NascentOxygen said:
The plate is a plane, extending out to infinity so there are no edge effects. The plane carries charge uniformly distributed. Field lines from these charges space themselves apart and never cross each other, so the only possible field lines arrangement is all perpendicular to the plane, like the hairs on the back of a frightened cat. These field lines extend out to infinity and remain parallel to each other. So no matter how far away from the plane, the field strength is uniform and undiminished.

Your equations were looking good until the last where r leapt in unheralded and uninvited!
Thank you for your reply! The thing is I do not know how to get rid of the r. If my equations were to work out, A would have to be 2\pi... And I have no idea why this would be the case. The only thing I can think of is that I have approached the question wrong and talking about the charge and area of the plate does not make sense. Instead I should be using the charge per unit area... Could that be it?
 
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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