The Electric Field Due to a Charged Disk

AI Thread Summary
The discussion centers on calculating the charge contained within a circular ring on a charged disk. The disk has a radius of 1.80 cm and a total charge of +2.15 x 10^6 elementary charges. The ring, with a width of 30 µm, is centered at a radius of 0.50 cm. Participants express confusion over the question's focus on charge rather than electric field calculations. The solution involves applying relevant equations to determine the charge within the specified ring width.
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Homework Statement


A circular plastic disk with radius R = 1.80 cm has a uniformly distributed charge of Q = + 2.15 106 e on one face. A circular ring of width 30 µm is centered on that face, with the center of the ring at radius r = 0.50 cm. What charge is contained within the width of the ring?


Homework Equations


E=σ/2ε(1-z/√(z^2+R^2 ))


The Attempt at a Solution



e=8.85e-12
o= 2.15e6
z=.5 cm
r= 1.8
Ans=3.15 e10
 
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I don't see it as an electric field question. The question asks "what charge ...".
 
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