The Field Equations of Newton: Understanding the Basics

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During Newton's time, the concept of fields did not exist, but his gravitational law can be expressed in terms of fields. The gravitational potential, represented as Φ, is a scalar field, while gravitational acceleration, denoted as g, is a vector field derived from the gradient of Φ. This formulation allows for the assignment of specific values and directions of gravitational force at every spatial location. The discussion highlights that while Newton did not explicitly use the term "field," the implications of his law inherently involve spatial considerations of distance and direction. Understanding these concepts is essential for grasping the relationship between gravity and spatial dimensions.
avito009
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Am I right when I say during Newton's time there was no idea of fields?

Now I have been looking for books and courses which are meant for amateurs. So I came across this video of one of my favourite professors Prof Leonard Susskind. http://theoreticalminimum.com/courses/general-relativity/2012/fall/lecture-9.

In this lecture he has mentioned about Newtons field equations. How can there be Newtons field equations? Can somebody explain me what it means and what the variables stand for?

F= ma= -m∇Φ(x)

a= -∇Φ(x)
 
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Newton didn't know about fields when he proposed his gravity law. But that doesn't mean his law can't be formulated in terms of fields.
In this formulation, there is a scalar field called \Phi called the gravitational potential and a vector field \vec g=-\vec \nabla \Phi called gravitational acceleration such that a particle at position \vec r has acceleration \vec g (\vec r).
 
The term "field" did not exist in Newton's time. However, the concept is implicit in Newton's gravitational law, because it assigns a particular value and direction of the force of gravity to every spatial location.
 
voko said:
it assigns a particular value and direction of the force of gravity to every spatial location.

Do you mean that the spatial location is the r (Distance from centre of object of mass M)? Also how does the vector "a" (Mentioned as "g" by Shyan) have a direction?
 
The magnitude of the force depends on the distance r between the objects and therefore on where in space the objects are located. Having a direction is what sets vectors apart from normal numbers. In the case of gravity, the force (and hence acceleration) has the direction "towards the gravitating body".
 
Poisson's equation, ## \nabla^2 \Phi = 4 \pi G \rho ##, is the appropriate field equation for Newtonian gravity. The potential Φ is a scalar, and g is a vector because it has for each space dimension the gradient of Φ along that dimension.
 
avito009 said:
Do you mean that the spatial location is the r (Distance from centre of object of mass M)?

You cannot say "a spatial location is the distance from something", because there are infinitely many spatial locations at a distance from something, all in different directions. In addition to the distance, you must specify a direction.
 

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