The Force of Gravity: Understanding Acceleration of 2-Kg Rocks

AI Thread Summary
The discussion centers on the force of gravity acting on two rocks of different masses, specifically a 2-kg rock and a 1-kg rock. It is established that while the gravitational force on the 2-kg rock is greater, both rocks experience the same acceleration due to gravity. The relationship between force, mass, and acceleration is explained using the formula F=ma, leading to the conclusion that acceleration remains constant regardless of mass. The mathematical breakdown shows that the acceleration of both rocks is equal, despite the difference in gravitational force. This illustrates a fundamental principle of physics: all objects fall at the same rate in a vacuum, regardless of their mass.
Stargate
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The force of gravity is twice as great on a 2-kg rock on a 1-kg rock. Why does the 2-kg rock not fall with twice the acceleration?
 
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Stargate said:
The force of gravity is twice as great on a 2-kg rock on a 1-kg rock. Why does the 2-kg rock not fall with twice the acceleration?


F=ma
If the force is the product between the mass and the acceleration,figure out yourself...

Daniel.
 
They both have the same mass and acceleration! Right?
 
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Stargate said:
They both have the same mass and acceleration! Right?

Okay,for the first body write
G_{1}=m_{1}a_{1}(1)
And for the second
G_{2}=m_{2}a_{2}(2)

Divide (1) through (2)
\frac{G_{1}}{G_{2}}=\frac{G_{1}a_{1}}{G_{2}a_{2}}(3)
Use the fact that G_{1} is two times G_{2} and that m_{1} is 2Kg,which is two times the value of m_{2} which is 1Kg.Then
2=\frac{2a_{1}}{a_{2}} \Rightarrow a_{1}=a_{2}

Daniel.
 
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