# The ideal spring and simple harmonic motion

1. Jun 24, 2009

### abvebstr19@co

1. The problem statement, all variables and given/known data

A person who weighs 665 N steps onto a spring scale in the bathroom, and the spring compresses by 0.67 cm.
(a) What is the spring constant?
(b) What is the weight of another person who compresses the spring by 0.37 cm?

2. Relevant equations

f=-Kx

frequency=(1/2pi)(k/m)^.5
frequency=1/T
where T=period

3. The attempt at a solution
f=kx
665N=K(.67cm)
K=992.53

2. Jun 24, 2009

### rock.freak667

So you basically want to to find F, for a given x and you know k. Just re-use the formula again.

3. Jun 24, 2009

### abvebstr19@co

thanks, i did that but the answer for that part is still wrong and i cant figure out why

4. Jun 24, 2009

### rock.freak667

5. Jun 24, 2009

### abvebstr19@co

there is none. its an online homework so they dont give answers untill after its due

6. Jun 24, 2009

### LowlyPion

Likely they want the answer in N/m, not N/cm