The logic of the self inductance formula

nabliat
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M_{12}=\frac{N_2\phi _{12}}{I_1}

i need to remmeber it

but i can't see the logic of
the formula
??
 
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nabliat said:
M_{12}=\frac{N_2\phi _{12}}{I_1}

i need to remmeber it

but i can't see the logic of
the formula
??

I thought the formula looked something like: \frac{\mu_{0}N^2 A}{l}. A is the cross section & magnetic field inside the solenoid is B=\mu_0 NI/l, flux through one loop is BA=\mu_0 N IA/l and \Phi= \mu_0 N^2 I A/l is the total flux. The inductance is just total flux divided by current.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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