The Mystery of the 'Wet' Asphalt: Explained

  • Thread starter Thread starter ms. confused
  • Start date Start date
  • Tags Tags
    Mystery
AI Thread Summary
Dry asphalt can appear wet on hot, sunny days due to the refraction of light caused by the warm air above it. The heat from the asphalt warms the surrounding air, making it less dense and altering how light travels. This refraction creates a visual effect that resembles a wet surface, reflecting the sky instead of the sun. The phenomenon is similar to a mirage, where the viewer perceives a false image. Understanding this optical illusion clarifies why asphalt can look deceptively shiny in heat.
ms. confused
Messages
90
Reaction score
0
Why does dry asphalt appear to be wet on a hot, sunny day?
 
Physics news on Phys.org
The hot asphalt warms the air around it, so when light strikes it, it's refracted upwards. (Hot air is less dense than cold air.) The refracted ray then meets your eye appearing to be shining/glowing from the asphalt instead of the sun/sky, a wet mirage develops which actually looks like the sky.
 
Check out this link on mirage!
http://www.suite101.com/article.cfm/science_sky/78177
 
Last edited by a moderator:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top