The probability of an electric car charging station being available

AI Thread Summary
To determine the probability of an electric car charging station being available upon arrival, one can analyze travel data, including journey frequencies and times. Given the presence of 50,000 charging stations across a country, calculations can be made based on geographical distribution. For instance, with the U.S. covering over 3 million square miles and approximately 39,300 square miles within one mile of a charging station, the probability of being near a station is roughly 0.0126%. This method allows for a rough estimate of availability based on location and travel patterns. Understanding these probabilities can aid in planning electric vehicle journeys more effectively.
bradyj7
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Hi there,

I'm just wondering if anybody would know of a way of determining the probability of an event.

I trying to figure out how I could calculate the probability of a charging station for an electric car being available when a person arrives at their destination.

I have the travel data for cars in terms of the number of journeys, journey start and end times and dates etc.

Say there is 50,000 charging stations in a country also.

Is there anyway of working out a rough estimate of this?

Thank you

John
 
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Sure you could say you want the probably that you will be in one mile of one and they are eventually distributed across the Continental United States there are 3,119,884.69 square miles and there are 39300 square miles that are within 1 mile of a charging station so the probability of a charging station being within 1 mile is 0.0125966%
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...
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