Lets say you take a 30 gram bullet and fire it out(adsbygoogle = window.adsbygoogle || []).push({});

of a barrel that gives the bullet a linear velocity of 86.6% of c

with no angular velocity.

Now it's mass would be 60 grams. Next you

accelerate the bullet angularly while it is in

motion,with a force that in no way affects the

bullet's linear motion.Assuming mechanical

failure isn't allowed, the bullet is angularly

accelerated until the bullet's mass becomes

90 grams. The bullet's linear velocity of 86.6%

of c won't be affected, since the angular

acceleration force acted perpendicular to the bullet's

linear motion.Relativistic momentum of the

bullet is given by p=gamma*(rest mass bullet)*v.

You now have a case where linear momentum of the

bullet at 86.6% of c,before angular acceleration

is(p=2*.03*.866*c),after angular acceleration of

the bullet,the linear momentum is now

(p=3*.03*.866*c).Why aren't these 2 momentums

equal since linear momentum must be conserved?

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# The relativistic bullet

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