The sum of an infinite geometric series

meeklobraca
Messages
188
Reaction score
0

Homework Statement



1+(x+1)+(x+1)^2+(x+1)^3 + ... if lx+1l < 1



Homework Equations



Sn=a/1-r



The Attempt at a Solution



My attempt:

so I have a = x+1 and r = x+1
from there i get x+1/1-(x+1)
which is x+1/1-x-1
from there x+1/-x
multiply by the reciprocal

my solution is x^2 + x + 1 with the 1 coming from the original sequence.

What do you think?
 
Physics news on Phys.org
I think the one should go and the answer is: -(x+1)/x (can you see why?)
 
So do I have everything correct until

from there x+1/-x?

If so then yes I see where you got it from.

x+1/-x the reciprocal is

x+1 multiplied by -1/x

correct?
 
Also, for this sequence, would 1 be the a variable? I have x+1 as the a variable but why wouldn't it be 1?
 
The first term in the series is 1. What does that tell you?
 
If 1 is the first term, then everything leading up to -(x+1)/x is wrong. So what is the first term?

If 1 is the first term then the answer is 1/-x? Can I leave the answer like that?
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top