- #1
Phillips101
- 33
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What's the worst case for the factorisation of n using trial division? Worst case in terms of arithmetic operations that is.
Many places tell me that it's n=pq with p and q prime and close to each other (and hence close to root(n) ), but I can't prove it.
Help would be appreciated.
Many places tell me that it's n=pq with p and q prime and close to each other (and hence close to root(n) ), but I can't prove it.
Help would be appreciated.