Theoretical Question about Buoyancy

AI Thread Summary
Archimedes' principle states that the buoyant force equals the weight of the displaced water. A frictionless box at the bottom of a lake raises the question of whether it experiences a buoyant force due to the absence of water beneath it. The discussion suggests that if all water were removed from underneath, buoyancy would not exist, seemingly contradicting Archimedes' principle. However, it is noted that complete removal of water is impossible, as water can always be present or forced beneath the box. The conversation also references an experiment with a ping-pong ball that illustrates buoyancy principles in a different context.
conkermaniac
Messages
11
Reaction score
0
This is a question that's been bothering me for a while. Archimedes's principle states that the weight of the water displaced is equal to the buoyant force. If a frictionless box sinks to the bottom of a lake, does it feel a buoyant force? Buoyancy exists because of a difference in pressure between the top and the bottom of the box. If the box is already at the bottom, then there can be no water underneath the box, and consequently no pressure exists underneath the box. If this is so, then does a buoyant force NOT exist? Doesn't this go against Archimedes' principle, which to the best of my knowledge does not contain any exceptions? :confused:

Thanks for your help! :)
 
Physics news on Phys.org
If you could remove all water from underneath the box, and there was no water below it, and there was no way water could slip under it (be pressed under it by pressure) and there was no water or air in the ground under it... well, there might be a case where Archimede's principle did not apply. Maybe there is something I'm missing...

But it doesen't matter, because you will never remove all the free matter from under it. There will always be water under it, or the water can be squeezed under it, or there is water in the ground etc...
 
I've been informed of a certain ping-pong ball experiment, where you put a ping-pong ball into an upside-down container that's been cut open at the other end. If you then pour water on top of the ping-pong ball, the ping-pong ball will stay at the bottom.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top