Theoretical Rope and Pulley Question

AI Thread Summary
Using free body diagrams, it's demonstrated that a pulley system allows for lifting heavier loads with the same applied force compared to using a rope alone. The applied force must exceed the gravitational force to lift an object off the ground without a pulley. A pulley system changes the direction of the force, making it easier to lift heavier weights. The discussion also touches on the concept of a movable pulley and the "block and tackle" system, which can further enhance lifting capabilities. Understanding these principles is crucial for solving related physics problems effectively.
qszwdxefc
Messages
10
Reaction score
0

Homework Statement



Demonstrate using free body diagrams and equations that, using the same force, a heavier load can be lifted with a rope and pulley system than with a rope alone.

2. The attempt at a solution

To lift something off the ground without a pulley, the applied force must be greater than the gravitational force.

With a pulley, the force you apply still must be great, but the pulley just changes the direction of the force/motion??

Thanks.
 
Physics news on Phys.org
Consider a movable pulley.
 
Does "block and tackle" sound familiar?
 
the only pulley system we have learned about is the atwood machine (weight connected to person through 1 pulley)
 
Instead of hanging blocks you could attach another pulley to a pulley.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top