Thermal Expansion of a Wire Connected To a Rod

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SUMMARY

The discussion focuses on the thermal expansion of a wire connected to a rod, specifically analyzing the elongation and stress calculations involved. The coefficient of linear expansion for copper was used to determine a change in length of 0.068%, while the natural strain of the wire was calculated at 0.048%. The additional stress was computed using Young's Modulus, leading to a final stress value of 41*10^6 N/m² after correcting arithmetic errors. The participants confirmed the approach but highlighted the need for accurate calculations.

PREREQUISITES
  • Understanding of thermal expansion principles, specifically ΔL = LαΔT
  • Familiarity with Young's Modulus and stress calculations
  • Knowledge of linear expansion coefficients, particularly for copper
  • Basic algebra for manipulating equations and performing calculations
NEXT STEPS
  • Review the derivation and application of the coefficient of linear expansion for various materials
  • Study the concept of Young's Modulus and its role in material stress analysis
  • Explore the relationship between strain and stress in materials under thermal conditions
  • Practice solving thermal expansion problems involving multiple connected materials
USEFUL FOR

Students in physics or engineering, particularly those studying material science, mechanics, or thermal dynamics, will benefit from this discussion.

person123
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Homework Statement


thermal expansion question.png


Homework Equations


ΔL=LαΔT
σ=EΔL/L

The Attempt at a Solution


For part a, I used the coefficient of linear expansion for copper and the change in temperature to find the change in length (0.068%). I thought part b had the same answer. The two are attached, and I would imagine that the elongation would be controlled by the thick rod rather than the thin wire. For part c , I found the length the natural strain of the wire due to thermal expansion (0.048%). I then took the difference between the actual strain and the natural strain and multiplied by young's modulus to find the additional stress (2.4*10^7 N/m^2). I then added that to the original stress (1.00*10^6 N/m^2) to get 2.5*10^7 N/m^2. Is this the correct approach? Thanks.
 

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person123 said:
For part c , I found the length the natural strain of the wire due to thermal expansion (0.048%).
Fine to here, but I am not quite clear on what you did next. Please post the details.
 
I knew that the wire would stretch 0.048% without the rod, but it is actually stretched 0.068%. I took the difference of the two values to find the additional strain due to the rod stretching the wire. I then multiplied that by Young's Modulus to find the additional stress:

σ=(2.0*10^11 N/m^2)(0.068%-0.048%)=2.4*10^7 N/m^2.

I then added that stress to the original stress the wire was under (1.00*10^6 N/m^2). This gave me the answer 2.5*10^7 N/m^2.
 
Last edited:
person123 said:
σ=(2.0*10^100 N/m^2)(0.068%-0.048%)=2.4*10^7 N/m^2.
I guess you meant 1011, not 10100, but the 2.4 is wrong.
 
Oh, I realized I made a careless error. It is 2*10^-4 . The final answer becomes 41*10^6 N/m^2. The answers just came up, and it's correct.
 
Last edited:
person123 said:
Yes, I meant 10^11
But the 2.4 is still wrong.
 
person123 said:

Homework Statement


View attachment 235607

Homework Equations


ΔL=LαΔT
σ=EΔL/L

The Attempt at a Solution


For part a, I used the coefficient of linear expansion for copper and the change in temperature to find the change in length (0.068%). I thought part b had the same answer. The two are attached, and I would imagine that the elongation would be controlled by the thick rod rather than the thin wire. For part c , I found the length the natural strain of the wire due to thermal expansion (0.048%). I then took the difference between the actual strain and the natural strain and multiplied by young's modulus to find the additional stress (2.4*10^7 N/m^2). I then added that to the original stress (1.00*10^6 N/m^2) to get 2.5*10^7 N/m^2. Is this the correct approach? Thanks.
I think that your conceptual approach is correct. I'm not so sure that you did the arithmetic correctly.
 

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