How Do You Calculate the Energy Conversion Efficiency of a Blower-Nozzle System?

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To calculate the energy conversion efficiency of a blower-nozzle system producing air at 30 m/s with a density of 1.1 kg/m³ and a nozzle diameter of 0.15 m, the flow rate must first be determined using the formula: flow rate = (density)(Area)(velocity). The area of the nozzle can be calculated from its diameter, allowing for the conversion of flow rate into mass flow rate in kg/s. Once the mass flow rate is established, the kinetic energy of the exiting air can be calculated using its velocity. Finally, the efficiency can be derived using the formula (power out/power in), where power out is the kinetic energy per second and power in is the input power of 1 hp.
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Homework Statement



The problem asks to find the energy conversion efficiency of a blower-nozzle combination that produces a velocity of 30m/s for air with a density of 1.1kg/mcubed. The nozzle has a diameter of .15m

input power is 1 hp

Homework Equations



given the flow rate = (density)(Area)(velocity)

The Attempt at a Solution



I know how to find the efficiency but do not know how to convert flow rate in (kg/s) to Power units in order to use (power out/power in) formula

Thanks for your help!
 
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Can you figure out the volume of air that exits the nozzle in 1 second?

And from that, can you use the velocity, and mass of that volume, to get it's kinetic energy?
 

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